1. d4 1… Nf6 2. Nf3 2… e6 3. e3 3… d5 4. Bd3 4… c5 5. O-O 5… b6 6. b3 6… Bb7 7. Bb2 7… Nbd7 8. Nbd2 8… Be7 9. Qe2 9… O-O 10. Ne5 10… Rc8 11. Rad1 11… Qc7 12. c4 12… dxc4 13. bxc4 13… Nxe5?! 14. dxe5 14… Nd7 15. f4 15… Nb8? 16. f5 16… Nc6?? 17. f6 17… Bd8?? 18. Bxh7 18… Kxh7 19. Qh5 19… Kg8 20. fxg7?! 20… Kxg7 21. Rf3?? 21… Nxe5?? 22. Bxe5 22… f6 23. Rg3# 1-0

Williams Brown

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#include#includeusing namespace std;int changes[6];int dp[1001];int dp1[1001];int main() { int n, m; cin >> n >> m; for (int i = 0; i < n; i++) cin >> changes[i]; dp1[m] = 1; for (int i = 0; i < n; i++) { int k = 0; int cnt = m; for (int j = 1; j * changes[i] <= m; j++) { dp1[m-j*changes[i]] = dp1[m - j * changes[i]] + dp1[0]; } } cout << dp1[m];}//if(j*changes[i]+changes[i+1]){// dp[++dp[0]]=j*changes[i]+changes[i+1]