1. Nf3 Nf6 2. d4 b6 3. c4 Bb7 4. Nc3 Bxf3 5. gxf3 Nc6 6. e4 e5 7. d5 Nd4 8. Be3 Bc5 9. f4 d6 10. f5 O-O 11. Rg1 g6 12. Bd3 Kh8 13. Bg5 gxf5 14. exf5 Rg8 15. h4 Rg7 16. Be2 Nxf5 17. Ne4 Rg6 18. h5 Rxg5 19. Rxg5 Nxe4 20. Rxf5 Qh4 21. Rxf7 Qh1 22. Bf1 Bxf2 23. Rxf2 Nxf2 24. Kxf2 Rf8 25. Ke2 Qh2 26. Kd3 Qg3 27. Kc2 Rf2 28. Be2 Qe3 29. Kb1 Rxe2 30. Qf1 Qe4 31. Kc1 Qc2# 0-1

Williams Brown

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#include#includeusing namespace std;int changes[6];int dp[1001];int dp1[1001];int main() { int n, m; cin >> n >> m; for (int i = 0; i < n; i++) cin >> changes[i]; dp1[m] = 1; for (int i = 0; i < n; i++) { int k = 0; int cnt = m; for (int j = 1; j * changes[i] <= m; j++) { dp1[m-j*changes[i]] = dp1[m - j * changes[i]] + dp1[0]; } } cout << dp1[m];}//if(j*changes[i]+changes[i+1]){// dp[++dp[0]]=j*changes[i]+changes[i+1]